soal 1
f(x) = 20 - 19 + x!!!
f(9) = ?
Soal 2
[tex] \sqrt{625} \times \sqrt{144} - \sqrt{9} = [/tex]
Nt: Woah bru main langsung juara pertama gilak seneng banget sih :)
1.
f(x) = 20 - 19 + x!!!
f(9) = 20 - 19 + 9!!!
f(9) = 20 - 19 + (9 × 6) × 3)
f(9) = 20 - 19 + (54 × 3)
f(9) = (20 - 19) + 162
f(9) = 1 + 162
f(9) = 163
2.
[tex] \sqrt{625} \times \sqrt{144} - \sqrt{9} [/tex]
[tex] = \sqrt{25 {}^{2} } \times \sqrt{144} - \sqrt{9} [/tex]
[tex] = 25 \times \sqrt{144} - \sqrt{9} [/tex]
[tex] = 25 \times \sqrt{12 {}^{2} } - \sqrt{9} [/tex]
[tex] = 25 \times 12 - \sqrt{9} [/tex]
[tex] = 25 \times 12 - \sqrt{3 {}^{2} } [/tex]
[tex] = (25 \times 12) - 3[/tex]
[tex] = 300 - 3[/tex]
[tex] = 297[/tex]
Kesimpulan hasil dari nomor 1 adalah : 163, dan nomor 2 adalah : 297
Penyelesaian soal :
[tex] \sf f(x) = 20 - 19 + x!!! [/tex]
[tex] \sf f(9) = 20 - 19 + x!!! [/tex]
[tex] \sf = 20 - 19 + 9!!! [/tex]
[tex] \sf = 20 - 19 + (9 \times 6 \times 3)[/tex]
[tex] \sf = 20 - 19 + (54 \times 3)[/tex]
[tex] \sf = 20 - 19 + 162[/tex]
[tex] \sf = 1 + 162[/tex]
[tex] \sf = 163[/tex]
[tex] \\ [/tex]
[tex] \sf \sqrt{625} \times \sqrt{144} - \sqrt{9} [/tex]
[tex] \sf = \sqrt{25} {}^{2} \times \sqrt{12} {}^{2} - \sqrt{3} {}^{2} [/tex]
[tex] \sf = \sqrt{25} \times \sqrt{12} - \sqrt{3} [/tex]
[tex] \sf = 25 \times 12 - 3[/tex]
[tex] \sf = 300 - 3[/tex]
[tex] \sf = 297[/tex]
[tex] \\ [/tex]
Tysm!
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